Blog #56 - Calculating the Voltage Vo Using Loop Analysis

As part of my problem series in this video, I will be Calculating the voltage V0 Using Loop analysis.

Once I am finished with this series of problems I will be posting them in my Stan store, at this web address…https://stan.store/GVB

Find V0 in this network using Loop analysis.

Since the network has two loops, or two meshes, we will need two equations to determine all the currents.

Note that since I2 goes directly through the current source, I2 must be 2∠0°A. therefore, one of our two equations is ready solved and…

I2 = 2∠0°…If we now apply KVL to the loop #1, we obtain…

−12 + I1through and times the two impedances (2 − j1) and since for the next two impedances the current will be the sum of (I1 - I2) so we must add the product of (I1 − I2) times (4 + j2) = 0…We now have two equations which will yield the mathematical solutions for the two currents….

Substituting for I2 from the first equation into the second now leaves us with one equation and one unknown, I1…removing the brackets yields…

-12 + 2I1 - jI1 + 4I1 - 8 + j2I1 - j4 = 0… I have coloured the I1 terms for clarity and collecting like terms moving the whole numbers to the right of the equation and keeping the variable on the left we get…I1(6 + j1) = 20 + j4…cross multiplying…which is the same as dividing both sides of the equation by (6 + J1)…

we get I1 = (20 + j4)/(6 + j1) or I1 is = 3.35∠1.85° A or (3.3 + j0.1) Amps…in both polar and rectangular coordinates. The voltage drop across the  4kΩ is V0 which is equal to 4(I1 − I2)… substituting our known values for the two currents…

V0 = 4 times I1 which we know is 3.35∠1.85° minus I2 which we know is 2∠0°)… converting to rectangular coordinates in order to perform the addition = 4 times 3.3 + j0.1 minus…2 @ 0° in rectangular coordinates is just 2 + j0.0… adding the two current results in…= 4(1.3 + j0.1)… finalizing the arithmetic the voltage is equal to…

= 5.2 + j0.4 Volts and 5.42∠4.57° Volts…in both polar and rectangular coordinates.

I want to introduce you to another product that’s out there that is worthy of paying attention to. The Anker SOLIX F2000 Generator. 

To find out more about this battery generator and to keep up-to-date on any sales or discounts are available simply go to the anchor site at this web address… And by using this web address…https://shrsl.com/4pplo…you can get $800 off the original price…. Or just browse through the various options on this site… There is no charge for just looking but you might find something that is available at a discounted price at this particular time.

Remember, this video has been brought to you by PSPT, where you will find electrical train training videos when you go to this web address…https://bit.ly/47YB3vh…which will also give you a free copy of my 50 page crib sheets that you can use while viewing any of the courses or just keep handy during your every day work.