From Ohm’s law for AC circuits, the current I can be described by the applied voltage E divided by the circuit impedance Z all of these of course are phasors…
I am letting the source voltage E be reference here so 120 Volts at 0 degrees looks like this…and the impedance Z being equal to 133.5∠41.5 deg. Therefore the current I = 120∠0 deg/133.5∠41.5 deg…or .899∠-41.5 Volts…which looks like the above…
Which means the current will be lagging the reference voltage by 41.5 deg.
Note: in my diagram, in order to fit the phasors comfortably on the slide, the magnitude of the current is exaggerated compared to the voltage, however the angles are correct.